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1214402430055 = 51031235577581
BaseRepresentation
bin10001101011000000000…
…001101000010001100111
311022002120210102100210211
4101223000001220101213
5124344044010230210
62325515550400251
7153511011224023
oct21530001502147
94262523370724
101214402430055
1142903056aa51
12177438b00087
138a6963a9279
1442ac5239383
15218c931238a
hex11ac0068467

1214402430055 has 8 divisors (see below), whose sum is σ = 1458696387744. Its totient is φ = 970579629600.

The previous prime is 1214402430029. The next prime is 1214402430079. The reversal of 1214402430055 is 5500342044121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1214402430055 - 29 = 1214402429543 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1214402429999 and 1214402430026.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117783636 + ... + 117793945.

It is an arithmetic number, because the mean of its divisors is an integer number (182337048468).

Almost surely, 21214402430055 is an apocalyptic number.

1214402430055 is a deficient number, since it is larger than the sum of its proper divisors (244293957689).

1214402430055 is a wasteful number, since it uses less digits than its factorization.

1214402430055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 235578617.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 1214402430055 its reverse (5500342044121), we get a palindrome (6714744474176).

The spelling of 1214402430055 in words is "one trillion, two hundred fourteen billion, four hundred two million, four hundred thirty thousand, fifty-five".

Divisors: 1 5 1031 5155 235577581 1177887905 242880486011 1214402430055