Base | Representation |
---|---|
bin | 1011000010111100000010… |
… | …0011010010011111100111 |
3 | 1121000001122010000100210111 |
4 | 2300233000203102133213 |
5 | 3042441132333201210 |
6 | 41455214443233451 |
7 | 2362311655236103 |
oct | 260570043223747 |
9 | 47001563010714 |
10 | 12145103022055 |
11 | 3962789040a43 |
12 | 1441976518887 |
13 | 6a1380571653 |
14 | 2ddb7cc48903 |
15 | 160dc6b4888a |
hex | b0bc08d27e7 |
12145103022055 has 8 divisors (see below), whose sum is σ = 14597668256400. Its totient is φ = 9700385997696.
The previous prime is 12145103022049. The next prime is 12145103022079. The reversal of 12145103022055 is 55022030154121.
12145103022055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12145103022055 - 25 = 12145103022023 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1962049090 + ... + 1962055279.
It is an arithmetic number, because the mean of its divisors is an integer number (1824708532050).
Almost surely, 212145103022055 is an apocalyptic number.
12145103022055 is a deficient number, since it is larger than the sum of its proper divisors (2452565234345).
12145103022055 is an equidigital number, since it uses as much as digits as its factorization.
12145103022055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3924104993.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 12145103022055 its reverse (55022030154121), we get a palindrome (67167133176176).
The spelling of 12145103022055 in words is "twelve trillion, one hundred forty-five billion, one hundred three million, twenty-two thousand, fifty-five".
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