1215004013 has 2 divisors, whose sum is σ = 1215004014. Its totient is φ = 1215004012.

The previous prime is 1215003997. The next prime is 1215004027. The reversal of 1215004013 is 3104005121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 739676809 + 475327204 = 27197^2 + 21802^2 .

It is a cyclic number.

It is not a de Polignac number, because 1215004013 - 2⁴ = 1215003997 is a prime.

It is a super-2 number, since 2×1215004013² = 2952469503212208338, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1215003982 and 1215004000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1215054013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607502006 + 607502007.

It is an arithmetic number, because the mean of its divisors is an integer number (607502007).

Almost surely, 2^1215004013 is an apocalyptic number.

It is an amenable number.

1215004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1215004013 is an equidigital number, since it uses as much as digits as its factorization.

1215004013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1215004013 is about 34856.9076798273. The cubic root of 1215004013 is about 1067.0691661451.

Adding to 1215004013 its reverse (3104005121), we get a palindrome (4319009134).

The spelling of 1215004013 in words is "one billion, two hundred fifteen million, four thousand, thirteen".