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12151331047 is a prime number
BaseRepresentation
bin10110101000100011…
…01001100011100111
31011100211212120112001
423110101221203213
5144341220043142
65325433110131
7610056416062
oct132421514347
934324776461
1012151331047
115176122959
122431558347
1311b860b51b
14833b718d9
154b1bb45b7
hex2d44698e7

12151331047 has 2 divisors, whose sum is σ = 12151331048. Its totient is φ = 12151331046.

The previous prime is 12151331033. The next prime is 12151331063. The reversal of 12151331047 is 74013315121.

12151331047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12151331047 is a prime.

It is a super-2 number, since 2×121513310472 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12151331347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6075665523 + 6075665524.

It is an arithmetic number, because the mean of its divisors is an integer number (6075665524).

Almost surely, 212151331047 is an apocalyptic number.

12151331047 is a deficient number, since it is larger than the sum of its proper divisors (1).

12151331047 is an equidigital number, since it uses as much as digits as its factorization.

12151331047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 28.

Adding to 12151331047 its reverse (74013315121), we get a palindrome (86164646168).

The spelling of 12151331047 in words is "twelve billion, one hundred fifty-one million, three hundred thirty-one thousand, forty-seven".