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12153532343411 is a prime number
BaseRepresentation
bin1011000011011011011011…
…1110100110010001110011
31121000212101120021020212202
42300312312332212101303
53043110413234442121
641503131121013415
72363030601262034
oct260666676462163
947025346236782
1012153532343411
113966314190928
12144352948426b
136a20c4a21174
1430033c54aa8b
1516121bb9a40b
hexb0db6fa6473

12153532343411 has 2 divisors, whose sum is σ = 12153532343412. Its totient is φ = 12153532343410.

The previous prime is 12153532343339. The next prime is 12153532343413. The reversal of 12153532343411 is 11434323535121.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12153532343411 - 222 = 12153528149107 is a prime.

It is a super-2 number, since 2×121535323434112 (a number of 27 digits) contains 22 as substring.

Together with 12153532343413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12153532343413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6076766171705 + 6076766171706.

It is an arithmetic number, because the mean of its divisors is an integer number (6076766171706).

Almost surely, 212153532343411 is an apocalyptic number.

12153532343411 is a deficient number, since it is larger than the sum of its proper divisors (1).

12153532343411 is an equidigital number, since it uses as much as digits as its factorization.

12153532343411 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129600, while the sum is 38.

Adding to 12153532343411 its reverse (11434323535121), we get a palindrome (23587855878532).

The spelling of 12153532343411 in words is "twelve trillion, one hundred fifty-three billion, five hundred thirty-two million, three hundred forty-three thousand, four hundred eleven".