12153844743 has 4 divisors (see below), whose sum is σ = 16205126328. Its totient is φ = 8102563160.

The previous prime is 12153844739. The next prime is 12153844789. The reversal of 12153844743 is 34744835121.

12153844743 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12153844743 - 2² = 12153844739 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12153844695 and 12153844704.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12153844723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2025640788 + ... + 2025640793.

It is an arithmetic number, because the mean of its divisors is an integer number (4051281582).

Almost surely, 2^12153844743 is an apocalyptic number.

12153844743 is a deficient number, since it is larger than the sum of its proper divisors (4051281585).

12153844743 is an equidigital number, since it uses as much as digits as its factorization.

12153844743 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4051281584.

The product of its digits is 322560, while the sum is 42.

The spelling of 12153844743 in words is "twelve billion, one hundred fifty-three million, eight hundred forty-four thousand, seven hundred forty-three".