Base | Representation |
---|---|
bin | 10110101000111001… |
… | …10101001001100011 |
3 | 1011101001101111012010 |
4 | 23110130311021203 |
5 | 144342442341430 |
6 | 5330020004003 |
7 | 610123344342 |
oct | 132434651143 |
9 | 34331344163 |
10 | 12154262115 |
11 | 5177845026 |
12 | 2432530603 |
13 | 11b90c6698 |
14 | 8342d5b59 |
15 | 4b2092cb0 |
hex | 2d4735263 |
12154262115 has 32 divisors (see below), whose sum is σ = 20602403136. Its totient is φ = 6097510400.
The previous prime is 12154262111. The next prime is 12154262147. The reversal of 12154262115 is 51126245121.
12154262115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12154262115 - 22 = 12154262111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12154262111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 472219 + ... + 497291.
It is an arithmetic number, because the mean of its divisors is an integer number (643825098).
Almost surely, 212154262115 is an apocalyptic number.
12154262115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12154262115 is a deficient number, since it is larger than the sum of its proper divisors (8448141021).
12154262115 is a wasteful number, since it uses less digits than its factorization.
12154262115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26999.
The product of its digits is 4800, while the sum is 30.
The spelling of 12154262115 in words is "twelve billion, one hundred fifty-four million, two hundred sixty-two thousand, one hundred fifteen".
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