Base | Representation |
---|---|
bin | 1011000011011110011101… |
… | …1011100110111010010111 |
3 | 1121000221111012220102022202 |
4 | 2300313213123212322113 |
5 | 3043114044341121201 |
6 | 41503343520315115 |
7 | 2363060002021253 |
oct | 260674733467227 |
9 | 47027435812282 |
10 | 12154345254551 |
11 | 39666a1040015 |
12 | 1443715772a9b |
13 | 6a21c4274986 |
14 | 3003b84b7263 |
15 | 161268222c6b |
hex | b0de76e6e97 |
12154345254551 has 2 divisors, whose sum is σ = 12154345254552. Its totient is φ = 12154345254550.
The previous prime is 12154345254533. The next prime is 12154345254577. The reversal of 12154345254551 is 15545254345121.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12154345254551 - 210 = 12154345253527 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12154345254496 and 12154345254505.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12154345254451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6077172627275 + 6077172627276.
It is an arithmetic number, because the mean of its divisors is an integer number (6077172627276).
Almost surely, 212154345254551 is an apocalyptic number.
12154345254551 is a deficient number, since it is larger than the sum of its proper divisors (1).
12154345254551 is an equidigital number, since it uses as much as digits as its factorization.
12154345254551 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2400000, while the sum is 47.
Adding to 12154345254551 its reverse (15545254345121), we get a palindrome (27699599599672).
The spelling of 12154345254551 in words is "twelve trillion, one hundred fifty-four billion, three hundred forty-five million, two hundred fifty-four thousand, five hundred fifty-one".
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