12154466512141 has 4 divisors (see below), whose sum is σ = 12205322020800. Its totient is φ = 12103611003484.

The previous prime is 12154466512109. The next prime is 12154466512159. The reversal of 12154466512141 is 14121566445121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12154466512141 - 2⁵ = 12154466512109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12154466512541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25427753971 + ... + 25427754448.

It is an arithmetic number, because the mean of its divisors is an integer number (3051330505200).

Almost surely, 2^{12154466512141} is an apocalyptic number.

It is an amenable number.

12154466512141 is a deficient number, since it is larger than the sum of its proper divisors (50855508659).

12154466512141 is an equidigital number, since it uses as much as digits as its factorization.

12154466512141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50855508658.

The product of its digits is 230400, while the sum is 43.

The spelling of 12154466512141 in words is "twelve trillion, one hundred fifty-four billion, four hundred sixty-six million, five hundred twelve thousand, one hundred forty-one".