Base | Representation |
---|---|
bin | 10110101001001011… |
… | …11000100000101111 |
3 | 1011101012212001102112 |
4 | 23110211320200233 |
5 | 144344044311213 |
6 | 5330142514235 |
7 | 610152460040 |
oct | 132445704057 |
9 | 34335761375 |
10 | 12156635183 |
11 | 5179115a40 |
12 | 243329597b |
13 | 11b9747874 |
14 | 8347528c7 |
15 | 4b23b0ea8 |
hex | 2d497882f |
12156635183 has 16 divisors (see below), whose sum is σ = 15160992000. Its totient is φ = 9469785600.
The previous prime is 12156635143. The next prime is 12156635209. The reversal of 12156635183 is 38153665121.
12156635183 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-12156635183 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12156635183.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12156635143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 246863 + ... + 291983.
It is an arithmetic number, because the mean of its divisors is an integer number (947562000).
Almost surely, 212156635183 is an apocalyptic number.
12156635183 is a deficient number, since it is larger than the sum of its proper divisors (3004356817).
12156635183 is a wasteful number, since it uses less digits than its factorization.
12156635183 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48638.
The product of its digits is 129600, while the sum is 41.
The spelling of 12156635183 in words is "twelve billion, one hundred fifty-six million, six hundred thirty-five thousand, one hundred eighty-three".
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