Base | Representation |
---|---|
bin | 10001101100100010011… |
… | …111011001101001101111 |
3 | 11022020211220220012210212 |
4 | 101230202133121221233 |
5 | 124410434411323042 |
6 | 2330351522053035 |
7 | 153566650602521 |
oct | 21544237315157 |
9 | 4266756805725 |
10 | 1216054401647 |
11 | 4297a9009728 |
12 | 17781a1aa17b |
13 | 8a89a70a957 |
14 | 42c007bba11 |
15 | 2197437a482 |
hex | 11b227d9a6f |
1216054401647 has 2 divisors, whose sum is σ = 1216054401648. Its totient is φ = 1216054401646.
The previous prime is 1216054401641. The next prime is 1216054401659. The reversal of 1216054401647 is 7461044506121.
It is a weak prime.
It is an emirp because it is prime and its reverse (7461044506121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1216054401647 - 220 = 1216053353071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1216054401641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 608027200823 + 608027200824.
It is an arithmetic number, because the mean of its divisors is an integer number (608027200824).
Almost surely, 21216054401647 is an apocalyptic number.
1216054401647 is a deficient number, since it is larger than the sum of its proper divisors (1).
1216054401647 is an equidigital number, since it uses as much as digits as its factorization.
1216054401647 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 161280, while the sum is 41.
Adding to 1216054401647 its reverse (7461044506121), we get a palindrome (8677098907768).
The spelling of 1216054401647 in words is "one trillion, two hundred sixteen billion, fifty-four million, four hundred one thousand, six hundred forty-seven".
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