Base | Representation |
---|---|
bin | 10110101001101110… |
… | …00010010010110110 |
3 | 1011101112022111111021 |
4 | 23110313002102312 |
5 | 144401222203302 |
6 | 5330423131354 |
7 | 610235625316 |
oct | 132467022266 |
9 | 34345274437 |
10 | 12161131702 |
11 | 5180707275 |
12 | 24348a3b5a |
13 | 11ba660425 |
14 | 8351a3446 |
15 | 4b299d437 |
hex | 2d4dc24b6 |
12161131702 has 4 divisors (see below), whose sum is σ = 18241697556. Its totient is φ = 6080565850.
The previous prime is 12161131691. The next prime is 12161131709. The reversal of 12161131702 is 20713116121.
12161131702 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20713116121 = 73877 ⋅280373.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12161131709) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3040282924 + ... + 3040282927.
It is an arithmetic number, because the mean of its divisors is an integer number (4560424389).
Almost surely, 212161131702 is an apocalyptic number.
12161131702 is a deficient number, since it is larger than the sum of its proper divisors (6080565854).
12161131702 is an equidigital number, since it uses as much as digits as its factorization.
12161131702 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6080565853.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 12161131702 its reverse (20713116121), we get a palindrome (32874247823).
The spelling of 12161131702 in words is "twelve billion, one hundred sixty-one million, one hundred thirty-one thousand, seven hundred two".
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