Base | Representation |
---|---|
bin | 1011000011111000011011… |
… | …0101001011010000000011 |
3 | 1121001121110220202212001010 |
4 | 2300332012311023100003 |
5 | 3043222333003023020 |
6 | 41510455235412003 |
7 | 2363424465445005 |
oct | 260760665132003 |
9 | 47047426685033 |
10 | 12161314501635 |
11 | 3969647a9a552 |
12 | 1444b3b754003 |
13 | 6a2a650a1010 |
14 | 300879d0a375 |
15 | 161524eb4de0 |
hex | b0f86d4b403 |
12161314501635 has 16 divisors (see below), whose sum is σ = 20954880372384. Its totient is φ = 5987108677632.
The previous prime is 12161314501519. The next prime is 12161314501663. The reversal of 12161314501635 is 53610541316121.
It is not a de Polignac number, because 12161314501635 - 210 = 12161314500611 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a junction number, because it is equal to n+sod(n) for n = 12161314501593 and 12161314501602.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31182857502 + ... + 31182857891.
It is an arithmetic number, because the mean of its divisors is an integer number (1309680023274).
Almost surely, 212161314501635 is an apocalyptic number.
12161314501635 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12161314501635 is a deficient number, since it is larger than the sum of its proper divisors (8793565870749).
12161314501635 is a wasteful number, since it uses less digits than its factorization.
12161314501635 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62365715414.
The product of its (nonzero) digits is 64800, while the sum is 39.
Adding to 12161314501635 its reverse (53610541316121), we get a palindrome (65771855817756).
The spelling of 12161314501635 in words is "twelve trillion, one hundred sixty-one billion, three hundred fourteen million, five hundred one thousand, six hundred thirty-five".
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