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12165263807 is a prime number
BaseRepresentation
bin10110101010001101…
…10011000110111111
31011101211002102200012
423111012303012333
5144403301420212
65331051453435
7610316015264
oct132506630677
934354072605
1012165263807
115182a79834
12243615727b
1311bb479168
1483595b26b
154b3017922
hex2d51b31bf

12165263807 has 2 divisors, whose sum is σ = 12165263808. Its totient is φ = 12165263806.

The previous prime is 12165263731. The next prime is 12165263809. The reversal of 12165263807 is 70836256121.

It is a strong prime.

It is an emirp because it is prime and its reverse (70836256121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12165263807 - 230 = 11091521983 is a prime.

Together with 12165263809, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12165263809) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6082631903 + 6082631904.

It is an arithmetic number, because the mean of its divisors is an integer number (6082631904).

Almost surely, 212165263807 is an apocalyptic number.

12165263807 is a deficient number, since it is larger than the sum of its proper divisors (1).

12165263807 is an equidigital number, since it uses as much as digits as its factorization.

12165263807 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120960, while the sum is 41.

The spelling of 12165263807 in words is "twelve billion, one hundred sixty-five million, two hundred sixty-three thousand, eight hundred seven".