Base | Representation |
---|---|
bin | 1011000101110110010100… |
… | …0110101010111010011001 |
3 | 1121011211201001221210122212 |
4 | 2301131211012222322121 |
5 | 3044301040222311133 |
6 | 41534204440124505 |
7 | 2366032104033233 |
oct | 261354506527231 |
9 | 47154631853585 |
10 | 12195108400793 |
11 | 3981a0984812a |
12 | 144b5b1166735 |
13 | 6a5cbc475656 |
14 | 302364179253 |
15 | 162351c02148 |
hex | b17651aae99 |
12195108400793 has 2 divisors, whose sum is σ = 12195108400794. Its totient is φ = 12195108400792.
The previous prime is 12195108400777. The next prime is 12195108400817. The reversal of 12195108400793 is 39700480159121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11366695331209 + 828413069584 = 3371453^2 + 910172^2 .
It is a cyclic number.
It is not a de Polignac number, because 12195108400793 - 24 = 12195108400777 is a prime.
It is not a weakly prime, because it can be changed into another prime (12195108100793) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6097554200396 + 6097554200397.
It is an arithmetic number, because the mean of its divisors is an integer number (6097554200397).
Almost surely, 212195108400793 is an apocalyptic number.
It is an amenable number.
12195108400793 is a deficient number, since it is larger than the sum of its proper divisors (1).
12195108400793 is an equidigital number, since it uses as much as digits as its factorization.
12195108400793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 50.
The spelling of 12195108400793 in words is "twelve trillion, one hundred ninety-five billion, one hundred eight million, four hundred thousand, seven hundred ninety-three".
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