Base | Representation |
---|---|
bin | 1011000110001000111100… |
… | …1110101110000011110111 |
3 | 1121012022121122120112012002 |
4 | 2301202033032232003313 |
5 | 3044341311142334312 |
6 | 41540353032245515 |
7 | 2366300046664421 |
oct | 261421716560367 |
9 | 47168548515162 |
10 | 12200110121207 |
11 | 398404611a768 |
12 | 145056824089b |
13 | 6a6608787328 |
14 | 3026ba567811 |
15 | 162545d984c2 |
hex | b188f3ae0f7 |
12200110121207 has 2 divisors, whose sum is σ = 12200110121208. Its totient is φ = 12200110121206.
The previous prime is 12200110121189. The next prime is 12200110121233. The reversal of 12200110121207 is 70212101100221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12200110121207 - 216 = 12200110055671 is a prime.
It is a super-2 number, since 2×122001101212072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12200110141207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100055060603 + 6100055060604.
It is an arithmetic number, because the mean of its divisors is an integer number (6100055060604).
Almost surely, 212200110121207 is an apocalyptic number.
12200110121207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12200110121207 is an equidigital number, since it uses as much as digits as its factorization.
12200110121207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 12200110121207 its reverse (70212101100221), we get a palindrome (82412211221428).
The spelling of 12200110121207 in words is "twelve trillion, two hundred billion, one hundred ten million, one hundred twenty-one thousand, two hundred seven".
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