Base | Representation |
---|---|
bin | 111000110011111100… |
… | …1011101100111011011 |
3 | 102122220112122221222221 |
4 | 1301213321131213123 |
5 | 3444330030413201 |
6 | 132014054324511 |
7 | 11546220412153 |
oct | 1614771354733 |
9 | 378815587887 |
10 | 122002201051 |
11 | 47817075435 |
12 | 1b78a359737 |
13 | b673c52513 |
14 | 5c95215763 |
15 | 3290b504a1 |
hex | 1c67e5d9db |
122002201051 has 2 divisors, whose sum is σ = 122002201052. Its totient is φ = 122002201050.
The previous prime is 122002201049. The next prime is 122002201133. The reversal of 122002201051 is 150102200221.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (150102200221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122002201051 - 21 = 122002201049 is a prime.
It is a super-2 number, since 2×1220022010512 (a number of 23 digits) contains 22 as substring.
Together with 122002201049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (122002801051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61001100525 + 61001100526.
It is an arithmetic number, because the mean of its divisors is an integer number (61001100526).
Almost surely, 2122002201051 is an apocalyptic number.
122002201051 is a deficient number, since it is larger than the sum of its proper divisors (1).
122002201051 is an equidigital number, since it uses as much as digits as its factorization.
122002201051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 16.
Adding to 122002201051 its reverse (150102200221), we get a palindrome (272104401272).
The spelling of 122002201051 in words is "one hundred twenty-two billion, two million, two hundred one thousand, fifty-one".
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