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12201110211131 is a prime number
BaseRepresentation
bin1011000110001100101011…
…0101110000101000111011
31121012102012100102100122122
42301203022311300220323
53044400333203224011
641541040155511455
72366333612421452
oct261431265605073
947172170370578
1012201110211131
1139845096a5066
1214507a715858b
136a6737a2640a
143027732d9b99
151625a3a963db
hexb18cad70a3b

12201110211131 has 2 divisors, whose sum is σ = 12201110211132. Its totient is φ = 12201110211130.

The previous prime is 12201110211071. The next prime is 12201110211133. The reversal of 12201110211131 is 13111201110221.

12201110211131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12201110211131 - 230 = 12200036469307 is a prime.

It is a super-2 number, since 2×122011102111312 (a number of 27 digits) contains 22 as substring.

Together with 12201110211133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12201110211133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100555105565 + 6100555105566.

It is an arithmetic number, because the mean of its divisors is an integer number (6100555105566).

Almost surely, 212201110211131 is an apocalyptic number.

12201110211131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12201110211131 is an equidigital number, since it uses as much as digits as its factorization.

12201110211131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 12201110211131 its reverse (13111201110221), we get a palindrome (25312311321352).

The spelling of 12201110211131 in words is "twelve trillion, two hundred one billion, one hundred ten million, two hundred eleven thousand, one hundred thirty-one".