| Base | Representation |
|---|---|
| bin | 111000110100001111… |
| … | …1010001100100110000 |
| 3 | 102122221020022112220120 |
| 4 | 1301220133101210300 |
| 5 | 3444340100110300 |
| 6 | 132015051010240 |
| 7 | 11546400564435 |
| oct | 1615037214460 |
| 9 | 378836275816 |
| 10 | 122012113200 |
| 11 | 4782172559a |
| 12 | 1b791739980 |
| 13 | b6760130b3 |
| 14 | 5c96675b8c |
| 15 | 329195c3a0 |
| hex | 1c687d1930 |
122012113200 has 240 divisors, whose sum is σ = 401899610112. Its totient is φ = 31622400000.
The previous prime is 122012113199. The next prime is 122012113219. The reversal of 122012113200 is 2311210221.
It is a tau number, because it is divible by the number of its divisors (240).
It is a super-2 number, since 2×1220121132002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 122012113200.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 13328625 + ... + 13337775.
Almost surely, 2122012113200 is an apocalyptic number.
122012113200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 122012113200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (200949805056).
122012113200 is an abundant number, since it is smaller than the sum of its proper divisors (279887496912).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
122012113200 is a wasteful number, since it uses less digits than its factorization.
122012113200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9484 (or 9473 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 122012113200 its reverse (2311210221), we get a palindrome (124323323421).
It can be divided in two parts, 1220121 and 13200, that added together give a palindrome (1233321).
The spelling of 122012113200 in words is "one hundred twenty-two billion, twelve million, one hundred thirteen thousand, two hundred".
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