Base | Representation |
---|---|
bin | 1011000110001101000011… |
… | …1111000001000110001101 |
3 | 1121012102110112101212112212 |
4 | 2301203100333001012031 |
5 | 3044401041101114013 |
6 | 41541054321240205 |
7 | 2366336303603423 |
oct | 261432077010615 |
9 | 47172415355485 |
10 | 12201213301133 |
11 | 398456190710a |
12 | 1450815793065 |
13 | 6a67531ac50c |
14 | 302782c93113 |
15 | 1625acb5b6a8 |
hex | b18d0fc118d |
12201213301133 has 8 divisors (see below), whose sum is σ = 12602570651136. Its totient is φ = 11800341565200.
The previous prime is 12201213301127. The next prime is 12201213301139. The reversal of 12201213301133 is 33110331210221.
It is an interprime number because it is at equal distance from previous prime (12201213301127) and next prime (12201213301139).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12201213301133 - 214 = 12201213284749 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12201213301099 and 12201213301108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12201213301139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 121352441 + ... + 121452942.
It is an arithmetic number, because the mean of its divisors is an integer number (1575321331392).
Almost surely, 212201213301133 is an apocalyptic number.
It is an amenable number.
12201213301133 is a deficient number, since it is larger than the sum of its proper divisors (401357350003).
12201213301133 is a wasteful number, since it uses less digits than its factorization.
12201213301133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 242807035.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12201213301133 its reverse (33110331210221), we get a palindrome (45311544511354).
It can be divided in two parts, 1220121 and 3301133, that added together give a palindrome (4521254).
The spelling of 12201213301133 in words is "twelve trillion, two hundred one billion, two hundred thirteen million, three hundred one thousand, one hundred thirty-three".
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