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12201321110302 = 26100660555151
BaseRepresentation
bin1011000110001101011101…
…1010010001101100011110
31121012102202001021010221001
42301203113122101230132
53044401301201012202
641541113132100514
72366342053142032
oct261432732215436
947172661233831
1012201321110302
1139846077517a5
12145084590473a
136a676c62861c
143027933181c2
151625b7354d87
hexb18d7691b1e

12201321110302 has 4 divisors (see below), whose sum is σ = 18301981665456. Its totient is φ = 6100660555150.

The previous prime is 12201321110233. The next prime is 12201321110309. The reversal of 12201321110302 is 20301112310221.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 12201321110302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12201321110309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3050330277574 + ... + 3050330277577.

It is an arithmetic number, because the mean of its divisors is an integer number (4575495416364).

Almost surely, 212201321110302 is an apocalyptic number.

12201321110302 is a deficient number, since it is larger than the sum of its proper divisors (6100660555154).

12201321110302 is an equidigital number, since it uses as much as digits as its factorization.

12201321110302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6100660555153.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12201321110302 its reverse (20301112310221), we get a palindrome (32502433420523).

The spelling of 12201321110302 in words is "twelve trillion, two hundred one billion, three hundred twenty-one million, one hundred ten thousand, three hundred two".

Divisors: 1 2 6100660555151 12201321110302