Base | Representation |
---|---|
bin | 1011000110001101011101… |
… | …1010010001101100011110 |
3 | 1121012102202001021010221001 |
4 | 2301203113122101230132 |
5 | 3044401301201012202 |
6 | 41541113132100514 |
7 | 2366342053142032 |
oct | 261432732215436 |
9 | 47172661233831 |
10 | 12201321110302 |
11 | 39846077517a5 |
12 | 145084590473a |
13 | 6a676c62861c |
14 | 3027933181c2 |
15 | 1625b7354d87 |
hex | b18d7691b1e |
12201321110302 has 4 divisors (see below), whose sum is σ = 18301981665456. Its totient is φ = 6100660555150.
The previous prime is 12201321110233. The next prime is 12201321110309. The reversal of 12201321110302 is 20301112310221.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 12201321110302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12201321110309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3050330277574 + ... + 3050330277577.
It is an arithmetic number, because the mean of its divisors is an integer number (4575495416364).
Almost surely, 212201321110302 is an apocalyptic number.
12201321110302 is a deficient number, since it is larger than the sum of its proper divisors (6100660555154).
12201321110302 is an equidigital number, since it uses as much as digits as its factorization.
12201321110302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6100660555153.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12201321110302 its reverse (20301112310221), we get a palindrome (32502433420523).
The spelling of 12201321110302 in words is "twelve trillion, two hundred one billion, three hundred twenty-one million, one hundred ten thousand, three hundred two".
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