Base | Representation |
---|---|
bin | 1011000110001101011111… |
… | …1101000100011100011111 |
3 | 1121012102202200102112021022 |
4 | 2301203113331010130133 |
5 | 3044401311014343241 |
6 | 41541114055354355 |
7 | 2366342223520142 |
oct | 261432775043437 |
9 | 47172680375238 |
10 | 12201330231071 |
11 | 3984611911323 |
12 | 14508489829bb |
13 | 6a677149cc27 |
14 | 302794610059 |
15 | 1625b805754b |
hex | b18d7f4471f |
12201330231071 has 2 divisors, whose sum is σ = 12201330231072. Its totient is φ = 12201330231070.
The previous prime is 12201330231001. The next prime is 12201330231073. The reversal of 12201330231071 is 17013203310221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12201330231071 - 214 = 12201330214687 is a prime.
Together with 12201330231073, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12201330231071.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12201330231073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100665115535 + 6100665115536.
It is an arithmetic number, because the mean of its divisors is an integer number (6100665115536).
Almost surely, 212201330231071 is an apocalyptic number.
12201330231071 is a deficient number, since it is larger than the sum of its proper divisors (1).
12201330231071 is an equidigital number, since it uses as much as digits as its factorization.
12201330231071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 12201330231071 its reverse (17013203310221), we get a palindrome (29214533541292).
The spelling of 12201330231071 in words is "twelve trillion, two hundred one billion, three hundred thirty million, two hundred thirty-one thousand, seventy-one".
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