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122014103 = 2314993539
BaseRepresentation
bin1110100010111…
…00100110010111
322111120221212212
413101130212113
5222213422403
620035104035
73011050151
oct721344627
9274527785
10122014103
1162968002
1234a4201b
131c3808c3
14122c1ad1
15aaa24d8
hex745c997

122014103 has 8 divisors (see below), whose sum is σ = 127440000. Its totient is φ = 116598328.

The previous prime is 122014099. The next prime is 122014111. The reversal of 122014103 is 301410221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 122014103 - 22 = 122014099 is a prime.

It is a super-3 number, since 3×1220141033 (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122014153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32708 + ... + 36246.

It is an arithmetic number, because the mean of its divisors is an integer number (15930000).

Almost surely, 2122014103 is an apocalyptic number.

122014103 is a deficient number, since it is larger than the sum of its proper divisors (5425897).

122014103 is a wasteful number, since it uses less digits than its factorization.

122014103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5061.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 122014103 is about 11045.9994115517. Note that the first 3 decimals coincide. The cubic root of 122014103 is about 495.9866766604.

Adding to 122014103 its reverse (301410221), we get a palindrome (423424324).

The spelling of 122014103 in words is "one hundred twenty-two million, fourteen thousand, one hundred three".

Divisors: 1 23 1499 3539 34477 81397 5304961 122014103