Base | Representation |
---|---|
bin | 10001110000011001101… |
… | …001111000010101101011 |
3 | 11022122112220200101112222 |
4 | 101300121221320111223 |
5 | 124442432441334011 |
6 | 2332315212424255 |
7 | 154104502253636 |
oct | 21603151702553 |
9 | 4278486611488 |
10 | 1220201121131 |
11 | 4305367a4423 |
12 | 178596a7808b |
13 | 8b0ab850015 |
14 | 430b5404c1d |
15 | 21b18432ddb |
hex | 11c19a7856b |
1220201121131 has 4 divisors (see below), whose sum is σ = 1220222442672. Its totient is φ = 1220179799592.
The previous prime is 1220201121121. The next prime is 1220201121143. The reversal of 1220201121131 is 1311211020221.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1220201121131 - 210 = 1220201120107 is a prime.
It is a super-2 number, since 2×12202011211312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1220201121121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10574696 + ... + 10689461.
It is an arithmetic number, because the mean of its divisors is an integer number (305055610668).
Almost surely, 21220201121131 is an apocalyptic number.
1220201121131 is a deficient number, since it is larger than the sum of its proper divisors (21321541).
1220201121131 is an equidigital number, since it uses as much as digits as its factorization.
1220201121131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21321540.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1220201121131 its reverse (1311211020221), we get a palindrome (2531412141352).
The spelling of 1220201121131 in words is "one trillion, two hundred twenty billion, two hundred one million, one hundred twenty-one thousand, one hundred thirty-one".
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