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12202022121041 is a prime number
BaseRepresentation
bin1011000110010000000100…
…1100011010111001010001
31121012111112220100011212202
42301210001030122321101
53044404220130333131
641541310453132545
72366365324503104
oct261440114327121
947174486304782
1012202022121041
113984937421515
121450a0062a155
136a685192ca8c
1430281c47673b
15162608b76bcb
hexb190131ae51

12202022121041 has 2 divisors, whose sum is σ = 12202022121042. Its totient is φ = 12202022121040.

The previous prime is 12202022120987. The next prime is 12202022121043. The reversal of 12202022121041 is 14012122020221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12201950210641 + 71910400 = 3493129^2 + 8480^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12202022121041 is a prime.

Together with 12202022121043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12202022121043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101011060520 + 6101011060521.

It is an arithmetic number, because the mean of its divisors is an integer number (6101011060521).

Almost surely, 212202022121041 is an apocalyptic number.

It is an amenable number.

12202022121041 is a deficient number, since it is larger than the sum of its proper divisors (1).

12202022121041 is an equidigital number, since it uses as much as digits as its factorization.

12202022121041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 20.

Adding to 12202022121041 its reverse (14012122020221), we get a palindrome (26214144141262).

The spelling of 12202022121041 in words is "twelve trillion, two hundred two billion, twenty-two million, one hundred twenty-one thousand, forty-one".