Base | Representation |
---|---|
bin | 11011101111101000111010… |
… | …011110110000110011011111 |
3 | 121000001002112102122011002022 |
4 | 123233220322132300303133 |
5 | 111443143003004201421 |
6 | 1111303401404050355 |
7 | 34462504116011333 |
oct | 3357507236606337 |
9 | 530032472564068 |
10 | 122021002022111 |
11 | 359748a8619065 |
12 | 118285a28339bb |
13 | 53116b9b3335a |
14 | 221bbc2d1b7c3 |
15 | e190a632e7ab |
hex | 6efa3a7b0cdf |
122021002022111 has 2 divisors, whose sum is σ = 122021002022112. Its totient is φ = 122021002022110.
The previous prime is 122021002022053. The next prime is 122021002022119. The reversal of 122021002022111 is 111220200120221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122021002022111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 122021002022111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122021002022119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61010501011055 + 61010501011056.
It is an arithmetic number, because the mean of its divisors is an integer number (61010501011056).
Almost surely, 2122021002022111 is an apocalyptic number.
122021002022111 is a deficient number, since it is larger than the sum of its proper divisors (1).
122021002022111 is an equidigital number, since it uses as much as digits as its factorization.
122021002022111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 122021002022111 its reverse (111220200120221), we get a palindrome (233241202142332).
The spelling of 122021002022111 in words is "one hundred twenty-two trillion, twenty-one billion, two million, twenty-two thousand, one hundred eleven".
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