Base | Representation |
---|---|
bin | 111000110100100110… |
… | …0110011001000011111 |
3 | 102122222001202212012011 |
4 | 1301221030303020133 |
5 | 3444401124002020 |
6 | 132020154452051 |
7 | 11546604200314 |
oct | 1615114631037 |
9 | 378861685164 |
10 | 122024047135 |
11 | 47828436751 |
12 | 1b795734027 |
13 | b678630cb3 |
14 | 5c980a0d0b |
15 | 3292a1835a |
hex | 1c6933321f |
122024047135 has 16 divisors (see below), whose sum is σ = 151163615232. Its totient is φ = 94463200800.
The previous prime is 122024047133. The next prime is 122024047153. The reversal of 122024047135 is 531740420221.
It is a happy number.
It is not a de Polignac number, because 122024047135 - 21 = 122024047133 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 122024047097 and 122024047106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122024047133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3218640 + ... + 3256330.
It is an arithmetic number, because the mean of its divisors is an integer number (9447725952).
Almost surely, 2122024047135 is an apocalyptic number.
122024047135 is a deficient number, since it is larger than the sum of its proper divisors (29139568097).
122024047135 is a wasteful number, since it uses less digits than its factorization.
122024047135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58614.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 122024047135 its reverse (531740420221), we get a palindrome (653764467356).
The spelling of 122024047135 in words is "one hundred twenty-two billion, twenty-four million, forty-seven thousand, one hundred thirty-five".
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