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1220304013100 = 225212203040131
BaseRepresentation
bin10001110000011111110…
…010011000011100101100
311022122211002021211210122
4101300133302120130230
5124443140311404400
62332333330024112
7154110161652344
oct21603762303454
94278732254718
101220304013100
11430589890707
12178605418038
138b0c6c66c43
14430c4d49d24
1521b224a9685
hex11c1fc9872c

1220304013100 has 18 divisors (see below), whose sum is σ = 2648059708644. Its totient is φ = 488121605200.

The previous prime is 1220304013079. The next prime is 1220304013169. The reversal of 1220304013100 is 13104030221.

It is a super-2 number, since 2×12203040131002 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6101519966 + ... + 6101520165.

It is an arithmetic number, because the mean of its divisors is an integer number (147114428258).

Almost surely, 21220304013100 is an apocalyptic number.

1220304013100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1220304013100 is an abundant number, since it is smaller than the sum of its proper divisors (1427755695544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1220304013100 is a wasteful number, since it uses less digits than its factorization.

1220304013100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12203040145 (or 12203040138 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1220304013100 its reverse (13104030221), we get a palindrome (1233408043321).

The spelling of 1220304013100 in words is "one trillion, two hundred twenty billion, three hundred four million, thirteen thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 12203040131 24406080262 48812160524 61015200655 122030401310 244060802620 305076003275 610152006550 1220304013100