Base | Representation |
---|---|
bin | 1011000110010101010010… |
… | …0001001010001001011111 |
3 | 1121012122011022211011101202 |
4 | 2301211110201022021133 |
5 | 3044420101014111044 |
6 | 41542101312030115 |
7 | 2366445061030412 |
oct | 261452441121137 |
9 | 47178138734352 |
10 | 12203420066399 |
11 | 3985494537561 |
12 | 145113083233b |
13 | 6a6a1543c293 |
14 | 302911db1b79 |
15 | 16268b762c4e |
hex | b195484a25f |
12203420066399 has 2 divisors, whose sum is σ = 12203420066400. Its totient is φ = 12203420066398.
The previous prime is 12203420066377. The next prime is 12203420066401. The reversal of 12203420066399 is 99366002430221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12203420066399 - 232 = 12199125099103 is a prime.
It is a super-2 number, since 2×122034200663992 (a number of 27 digits) contains 22 as substring.
Together with 12203420066401, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12203420066359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101710033199 + 6101710033200.
It is an arithmetic number, because the mean of its divisors is an integer number (6101710033200).
Almost surely, 212203420066399 is an apocalyptic number.
12203420066399 is a deficient number, since it is larger than the sum of its proper divisors (1).
12203420066399 is an equidigital number, since it uses as much as digits as its factorization.
12203420066399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 839808, while the sum is 47.
The spelling of 12203420066399 in words is "twelve trillion, two hundred three billion, four hundred twenty million, sixty-six thousand, three hundred ninety-nine".
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