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12203535433 is a prime number
BaseRepresentation
bin10110101110110001…
…10010110001001001
31011111111002211110211
423113120302301021
5144443101113213
65334540041121
7611262224335
oct132730626111
934444084424
1012203535433
1151a2639881
122446b331a1
1311c63890ab
1483aa807c5
154b657753d
hex2d7632c49

12203535433 has 2 divisors, whose sum is σ = 12203535434. Its totient is φ = 12203535432.

The previous prime is 12203535389. The next prime is 12203535439. The reversal of 12203535433 is 33453530221.

12203535433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12203179024 + 356409 = 110468^2 + 597^2 .

It is a cyclic number.

It is not a de Polignac number, because 12203535433 - 225 = 12169981001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12203535395 and 12203535404.

It is not a weakly prime, because it can be changed into another prime (12203535439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101767716 + 6101767717.

It is an arithmetic number, because the mean of its divisors is an integer number (6101767717).

Almost surely, 212203535433 is an apocalyptic number.

It is an amenable number.

12203535433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12203535433 is an equidigital number, since it uses as much as digits as its factorization.

12203535433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 31.

The spelling of 12203535433 in words is "twelve billion, two hundred three million, five hundred thirty-five thousand, four hundred thirty-three".