Base | Representation |
---|---|
bin | 111000110101000101… |
… | …1001100000001011101 |
3 | 102200000012112202212101 |
4 | 1301222023030001131 |
5 | 3444414320331023 |
6 | 132021541205101 |
7 | 11550163205215 |
oct | 1615213140135 |
9 | 380005482771 |
10 | 122040402013 |
11 | 47836697382 |
12 | 1b79b100791 |
13 | b67bb3923a |
14 | 5c9a31b245 |
15 | 32941991ad |
hex | 1c6a2cc05d |
122040402013 has 2 divisors, whose sum is σ = 122040402014. Its totient is φ = 122040402012.
The previous prime is 122040401993. The next prime is 122040402023. The reversal of 122040402013 is 310204040221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89776339129 + 32264062884 = 299627^2 + 179622^2 .
It is a cyclic number.
It is not a de Polignac number, because 122040402013 - 25 = 122040401981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122040402023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61020201006 + 61020201007.
It is an arithmetic number, because the mean of its divisors is an integer number (61020201007).
Almost surely, 2122040402013 is an apocalyptic number.
It is an amenable number.
122040402013 is a deficient number, since it is larger than the sum of its proper divisors (1).
122040402013 is an equidigital number, since it uses as much as digits as its factorization.
122040402013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 122040402013 its reverse (310204040221), we get a palindrome (432244442234).
The spelling of 122040402013 in words is "one hundred twenty-two billion, forty million, four hundred two thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 1.016 sec. • engine limits •