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1220431140311 is a prime number
BaseRepresentation
bin10001110000100111010…
…111010101010111010111
311022200010221111120112212
4101300213113111113113
5124443420332442221
62332354110504035
7154113264346535
oct21604727252727
94280127446485
101220431140311
11430644620219
1217863bb0501b
138b1173b7c46
14430d7b9d155
1521b2d71bb5b
hex11c275d55d7

1220431140311 has 2 divisors, whose sum is σ = 1220431140312. Its totient is φ = 1220431140310.

The previous prime is 1220431140283. The next prime is 1220431140319. The reversal of 1220431140311 is 1130411340221.

It is a strong prime.

It is an emirp because it is prime and its reverse (1130411340221) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1220431140311 is a prime.

It is a super-3 number, since 3×12204311403113 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1220431140319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610215570155 + 610215570156.

It is an arithmetic number, because the mean of its divisors is an integer number (610215570156).

Almost surely, 21220431140311 is an apocalyptic number.

1220431140311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1220431140311 is an equidigital number, since it uses as much as digits as its factorization.

1220431140311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1220431140311 its reverse (1130411340221), we get a palindrome (2350842480532).

The spelling of 1220431140311 in words is "one trillion, two hundred twenty billion, four hundred thirty-one million, one hundred forty thousand, three hundred eleven".