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12210040133 is a prime number
BaseRepresentation
bin10110101111100011…
…00110110101000101
31011111221100022020122
423113301212311011
5200001232241013
65335331311325
7611401425434
oct132761466505
934457308218
1012210040133
1151a6281965
12244914b545
1311c7825a25
1483b89511b
154b6e0ea08
hex2d7c66d45

12210040133 has 2 divisors, whose sum is σ = 12210040134. Its totient is φ = 12210040132.

The previous prime is 12210040123. The next prime is 12210040159. The reversal of 12210040133 is 33104001221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12107261089 + 102779044 = 110033^2 + 10138^2 .

It is a cyclic number.

It is not a de Polignac number, because 12210040133 - 218 = 12209777989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12210040123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105020066 + 6105020067.

It is an arithmetic number, because the mean of its divisors is an integer number (6105020067).

Almost surely, 212210040133 is an apocalyptic number.

It is an amenable number.

12210040133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12210040133 is an equidigital number, since it uses as much as digits as its factorization.

12210040133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12210040133 its reverse (33104001221), we get a palindrome (45314041354).

The spelling of 12210040133 in words is "twelve billion, two hundred ten million, forty thousand, one hundred thirty-three".