Base | Representation |
---|---|
bin | 1011000110101110001101… |
… | …1000111011111010100011 |
3 | 1121020021102200220122010222 |
4 | 2301223203120323322203 |
5 | 3100022302134121011 |
6 | 41545125323513255 |
7 | 2400102646505534 |
oct | 261534330737243 |
9 | 47207380818128 |
10 | 12210112020131 |
11 | 3988308a11433 |
12 | 145249998882b |
13 | 6a754098ac0c |
14 | 302d88a6268b |
15 | 16292decdddb |
hex | b1ae363bea3 |
12210112020131 has 2 divisors, whose sum is σ = 12210112020132. Its totient is φ = 12210112020130.
The previous prime is 12210112020107. The next prime is 12210112020143. The reversal of 12210112020131 is 13102021101221.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12210112020131 - 210 = 12210112019107 is a prime.
It is a super-2 number, since 2×122101120201312 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (12210112020101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105056010065 + 6105056010066.
It is an arithmetic number, because the mean of its divisors is an integer number (6105056010066).
Almost surely, 212210112020131 is an apocalyptic number.
12210112020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12210112020131 is an equidigital number, since it uses as much as digits as its factorization.
12210112020131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 12210112020131 its reverse (13102021101221), we get a palindrome (25312133121352).
The spelling of 12210112020131 in words is "twelve trillion, two hundred ten billion, one hundred twelve million, twenty thousand, one hundred thirty-one".
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