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12210312121523 is a prime number
BaseRepresentation
bin1011000110101110111101…
…0100010000110010110011
31121020021221122102211122122
42301223233110100302303
53100023204400342043
641545201232424455
72400110626364525
oct261535724206263
947207848384578
1012210312121523
11398840096358a
1214525349a812b
136a757327c3c9
14302da746da15
15162941858368
hexb1aef510cb3

12210312121523 has 2 divisors, whose sum is σ = 12210312121524. Its totient is φ = 12210312121522.

The previous prime is 12210312121507. The next prime is 12210312121531. The reversal of 12210312121523 is 32512121301221.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12210312121523 - 24 = 12210312121507 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12210312121492 and 12210312121501.

It is not a weakly prime, because it can be changed into another prime (12210312151523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105156060761 + 6105156060762.

It is an arithmetic number, because the mean of its divisors is an integer number (6105156060762).

Almost surely, 212210312121523 is an apocalyptic number.

12210312121523 is a deficient number, since it is larger than the sum of its proper divisors (1).

12210312121523 is an equidigital number, since it uses as much as digits as its factorization.

12210312121523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 12210312121523 its reverse (32512121301221), we get a palindrome (44722433422744).

The spelling of 12210312121523 in words is "twelve trillion, two hundred ten billion, three hundred twelve million, one hundred twenty-one thousand, five hundred twenty-three".