Search a number
-
+
12211100120081 is a prime number
BaseRepresentation
bin1011000110110001111001…
…0010001111010000010001
31121020100222120012022110102
42301230132102033100101
53100031313112320311
641545411342142145
72400136305304442
oct261543622172021
947210876168412
1012211100120081
113988775747565
121452714881955
136a766a5bc745
1430303dd932c9
1516298ab0e43b
hexb1b1e48f411

12211100120081 has 2 divisors, whose sum is σ = 12211100120082. Its totient is φ = 12211100120080.

The previous prime is 12211100120059. The next prime is 12211100120083. The reversal of 12211100120081 is 18002100111221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10051537613056 + 2159562507025 = 3170416^2 + 1469545^2 .

It is a cyclic number.

It is not a de Polignac number, because 12211100120081 - 238 = 11936222213137 is a prime.

It is a super-2 number, since 2×122111001200812 (a number of 27 digits) contains 22 as substring.

Together with 12211100120083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12211100120083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105550060040 + 6105550060041.

It is an arithmetic number, because the mean of its divisors is an integer number (6105550060041).

Almost surely, 212211100120081 is an apocalyptic number.

It is an amenable number.

12211100120081 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211100120081 is an equidigital number, since it uses as much as digits as its factorization.

12211100120081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 20.

The spelling of 12211100120081 in words is "twelve trillion, two hundred eleven billion, one hundred million, one hundred twenty thousand, eighty-one".