1221114113 has 2 divisors, whose sum is σ = 1221114114. Its totient is φ = 1221114112.

The previous prime is 1221114101. The next prime is 1221114121. The reversal of 1221114113 is 3114111221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1159538704 + 61575409 = 34052^2 + 7847^2 .

It is a cyclic number.

It is not a de Polignac number, because 1221114113 - 2¹⁴ = 1221097729 is a prime.

It is a super-2 number, since 2×1221114113² = 2982239353935553538, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1221114091 and 1221114100.

It is not a weakly prime, because it can be changed into another prime (1221114133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610557056 + 610557057.

It is an arithmetic number, because the mean of its divisors is an integer number (610557057).

Almost surely, 2^1221114113 is an apocalyptic number.

It is an amenable number.

1221114113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221114113 is an equidigital number, since it uses as much as digits as its factorization.

1221114113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48, while the sum is 17.

The square root of 1221114113 is about 34944.4432349408. The cubic root of 1221114113 is about 1068.8548942656.

Adding to 1221114113 its reverse (3114111221), we get a palindrome (4335225334).

The spelling of 1221114113 in words is "one billion, two hundred twenty-one million, one hundred fourteen thousand, one hundred thirteen".