Base | Representation |
---|---|
bin | 11011110000111101101011… |
… | …000110110010001111100111 |
3 | 121000100210110002012211100001 |
4 | 123300331223012302033213 |
5 | 112001140400101231401 |
6 | 1111413252310402131 |
7 | 34502205332130532 |
oct | 3360755306621747 |
9 | 530323402184301 |
10 | 122112012133351 |
11 | 359aa460439729 |
12 | 11842161960347 |
13 | 531a161cc2b96 |
14 | 2222378039a19 |
15 | e1b6311d8601 |
hex | 6f0f6b1b23e7 |
122112012133351 has 2 divisors, whose sum is σ = 122112012133352. Its totient is φ = 122112012133350.
The previous prime is 122112012133273. The next prime is 122112012133381. The reversal of 122112012133351 is 153331210211221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122112012133351 - 245 = 86927640044519 is a prime.
It is a super-2 number, since 2×1221120121333512 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122112012133381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61056006066675 + 61056006066676.
It is an arithmetic number, because the mean of its divisors is an integer number (61056006066676).
Almost surely, 2122112012133351 is an apocalyptic number.
122112012133351 is a deficient number, since it is larger than the sum of its proper divisors (1).
122112012133351 is an equidigital number, since it uses as much as digits as its factorization.
122112012133351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 28.
Adding to 122112012133351 its reverse (153331210211221), we get a palindrome (275443222344572).
The spelling of 122112012133351 in words is "one hundred twenty-two trillion, one hundred twelve billion, twelve million, one hundred thirty-three thousand, three hundred fifty-one".
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