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12211213133303 is a prime number
BaseRepresentation
bin1011000110110010010100…
…0001010110010111110111
31121020101021102211222110022
42301230211001112113313
53100032031030231203
641545430500315355
72400142150016162
oct261544501262767
947211242758408
1012211213133303
113988823517018
1214527466a2b5b
136a7687b3b482
14303050db0ad9
151629959d4a38
hexb1b250565f7

12211213133303 has 2 divisors, whose sum is σ = 12211213133304. Its totient is φ = 12211213133302.

The previous prime is 12211213133261. The next prime is 12211213133363. The reversal of 12211213133303 is 30333131211221.

It is a weak prime.

It is an emirp because it is prime and its reverse (30333131211221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12211213133303 - 214 = 12211213116919 is a prime.

It is a super-2 number, since 2×122112131333032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12211213133363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105606566651 + 6105606566652.

It is an arithmetic number, because the mean of its divisors is an integer number (6105606566652).

Almost surely, 212211213133303 is an apocalyptic number.

12211213133303 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211213133303 is an equidigital number, since it uses as much as digits as its factorization.

12211213133303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 26.

Adding to 12211213133303 its reverse (30333131211221), we get a palindrome (42544344344524).

The spelling of 12211213133303 in words is "twelve trillion, two hundred eleven billion, two hundred thirteen million, one hundred thirty-three thousand, three hundred three".