Base | Representation |
---|---|
bin | 1011000110110010011000… |
… | …1001010100110000010111 |
3 | 1121020101022202100120010122 |
4 | 2301230212021110300113 |
5 | 3100032100343013142 |
6 | 41545432412542155 |
7 | 2400142466261162 |
oct | 261544611246027 |
9 | 47211282316118 |
10 | 12211232001047 |
11 | 39888331336a2 |
12 | 1452750a8195b |
13 | 6a768ba16411 |
14 | 3030536c2ad9 |
15 | 1629974b01d2 |
hex | b1b26254c17 |
12211232001047 has 2 divisors, whose sum is σ = 12211232001048. Its totient is φ = 12211232001046.
The previous prime is 12211232000987. The next prime is 12211232001113. The reversal of 12211232001047 is 74010023211221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12211232001047 - 26 = 12211232000983 is a prime.
It is a super-2 number, since 2×122112320010472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12211232501047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105616000523 + 6105616000524.
It is an arithmetic number, because the mean of its divisors is an integer number (6105616000524).
Almost surely, 212211232001047 is an apocalyptic number.
12211232001047 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211232001047 is an equidigital number, since it uses as much as digits as its factorization.
12211232001047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 12211232001047 its reverse (74010023211221), we get a palindrome (86221255212268).
The spelling of 12211232001047 in words is "twelve trillion, two hundred eleven billion, two hundred thirty-two million, one thousand, forty-seven".
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