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122113100120153 is a prime number
BaseRepresentation
bin11011110000111110101011…
…111101001000000001011001
3121000100220020220110021122112
4123300332223331020001121
5112001200112112321103
61111413552254002105
734502244312640652
oct3360765375100131
9530326226407575
10122113100120153
11359aa96959927a
12118424061a6335
13531a2a652885c
14222243c72c529
15e1b696999cd8
hex6f0fabf48059

122113100120153 has 2 divisors, whose sum is σ = 122113100120154. Its totient is φ = 122113100120152.

The previous prime is 122113100120147. The next prime is 122113100120159. The reversal of 122113100120153 is 351021001311221.

It is a balanced prime because it is at equal distance from previous prime (122113100120147) and next prime (122113100120159).

It can be written as a sum of positive squares in only one way, i.e., 76344046050064 + 45769054070089 = 8737508^2 + 6765283^2 .

It is a cyclic number.

It is not a de Polignac number, because 122113100120153 - 28 = 122113100119897 is a prime.

It is not a weakly prime, because it can be changed into another prime (122113100120159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61056550060076 + 61056550060077.

It is an arithmetic number, because the mean of its divisors is an integer number (61056550060077).

Almost surely, 2122113100120153 is an apocalyptic number.

It is an amenable number.

122113100120153 is a deficient number, since it is larger than the sum of its proper divisors (1).

122113100120153 is an equidigital number, since it uses as much as digits as its factorization.

122113100120153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 122113100120153 its reverse (351021001311221), we get a palindrome (473134101431374).

The spelling of 122113100120153 in words is "one hundred twenty-two trillion, one hundred thirteen billion, one hundred million, one hundred twenty thousand, one hundred fifty-three".