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1221131020477 is a prime number
BaseRepresentation
bin10001110001010001000…
…101001010100010111101
311022201221201110011122111
4101301101011022202331
5130001334020123402
62332551351414021
7154136523261514
oct21612105124275
94281851404574
101221131020477
11430973698585
121787b6384311
138b1c93b4914
1443162b0567b
1521b6edb89d7
hex11c5114a8bd

1221131020477 has 2 divisors, whose sum is σ = 1221131020478. Its totient is φ = 1221131020476.

The previous prime is 1221131020457. The next prime is 1221131020489. The reversal of 1221131020477 is 7740201311221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 885535578841 + 335595441636 = 941029^2 + 579306^2 .

It is a cyclic number.

It is not a de Polignac number, because 1221131020477 - 27 = 1221131020349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1221131020427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610565510238 + 610565510239.

It is an arithmetic number, because the mean of its divisors is an integer number (610565510239).

Almost surely, 21221131020477 is an apocalyptic number.

It is an amenable number.

1221131020477 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221131020477 is an equidigital number, since it uses as much as digits as its factorization.

1221131020477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4704, while the sum is 31.

Adding to 1221131020477 its reverse (7740201311221), we get a palindrome (8961332331698).

The spelling of 1221131020477 in words is "one trillion, two hundred twenty-one billion, one hundred thirty-one million, twenty thousand, four hundred seventy-seven".