12211314503 has 2 divisors, whose sum is σ = 12211314504. Its totient is φ = 12211314502.

The previous prime is 12211314487. The next prime is 12211314569. The reversal of 12211314503 is 30541311221.

It is a weak prime.

It is an emirp because it is prime and its reverse (30541311221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12211314503 - 2⁴ = 12211314487 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12211334503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105657251 + 6105657252.

It is an arithmetic number, because the mean of its divisors is an integer number (6105657252).

Almost surely, 2^12211314503 is an apocalyptic number.

12211314503 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211314503 is an equidigital number, since it uses as much as digits as its factorization.

12211314503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 12211314503 its reverse (30541311221), we get a palindrome (42752625724).

The spelling of 12211314503 in words is "twelve billion, two hundred eleven million, three hundred fourteen thousand, five hundred three".