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122113231301023 is a prime number
BaseRepresentation
bin11011110000111110110011…
…110001100010100110011111
3121000100220121001021221222021
4123300332303301202212133
5112001200344203113043
61111414013301401011
734502250464650324
oct3360766361424637
9530326531257867
10122113231301023
11359aaa26647416
1211842442109167
13531a2c7768981
142222451d18b4b
15e1b6a325d3ed
hex6f0fb3c6299f

122113231301023 has 2 divisors, whose sum is σ = 122113231301024. Its totient is φ = 122113231301022.

The previous prime is 122113231301021. The next prime is 122113231301213. The reversal of 122113231301023 is 320103132311221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 122113231301023 - 21 = 122113231301021 is a prime.

It is a super-2 number, since 2×1221132313010232 (a number of 29 digits) contains 22 as substring.

Together with 122113231301021, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122113231301021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61056615650511 + 61056615650512.

It is an arithmetic number, because the mean of its divisors is an integer number (61056615650512).

Almost surely, 2122113231301023 is an apocalyptic number.

122113231301023 is a deficient number, since it is larger than the sum of its proper divisors (1).

122113231301023 is an equidigital number, since it uses as much as digits as its factorization.

122113231301023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 122113231301023 its reverse (320103132311221), we get a palindrome (442216363612244).

The spelling of 122113231301023 in words is "one hundred twenty-two trillion, one hundred thirteen billion, two hundred thirty-one million, three hundred one thousand, twenty-three".