Base | Representation |
---|---|
bin | 11011110001000101001101… |
… | …110010000100111010001111 |
3 | 121000101120100102222011100212 |
4 | 123301011031302010322033 |
5 | 112001303441141200421 |
6 | 1111421112030113035 |
7 | 34502613112534214 |
oct | 3361051562047217 |
9 | 530346312864325 |
10 | 122120110100111 |
11 | 35a02936539a42 |
12 | 1184384194b77b |
13 | 531ab529171a6 |
14 | 2222905725b0b |
15 | e1b9570d5e5b |
hex | 6f114dc84e8f |
122120110100111 has 2 divisors, whose sum is σ = 122120110100112. Its totient is φ = 122120110100110.
The previous prime is 122120110100069. The next prime is 122120110100171. The reversal of 122120110100111 is 111001011021221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122120110100111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122120110100171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61060055050055 + 61060055050056.
It is an arithmetic number, because the mean of its divisors is an integer number (61060055050056).
Almost surely, 2122120110100111 is an apocalyptic number.
122120110100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
122120110100111 is an equidigital number, since it uses as much as digits as its factorization.
122120110100111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 122120110100111 its reverse (111001011021221), we get a palindrome (233121121121332).
The spelling of 122120110100111 in words is "one hundred twenty-two trillion, one hundred twenty billion, one hundred ten million, one hundred thousand, one hundred eleven".
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