Base | Representation |
---|---|
bin | 10001110001010101011… |
… | …000111110000111011111 |
3 | 11022202010202111102202011 |
4 | 101301111120332013133 |
5 | 130002011022240221 |
6 | 2333002453212051 |
7 | 154141361650231 |
oct | 21612530760737 |
9 | 4282122442664 |
10 | 1221203321311 |
11 | 430a00490236 |
12 | 178816631027 |
13 | 8b20b37a78c |
14 | 4316c566251 |
15 | 21b763eb1e1 |
hex | 11c5563e1df |
1221203321311 has 2 divisors, whose sum is σ = 1221203321312. Its totient is φ = 1221203321310.
The previous prime is 1221203321291. The next prime is 1221203321329. The reversal of 1221203321311 is 1131233021221.
It is a strong prime.
It is an emirp because it is prime and its reverse (1131233021221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1221203321311 - 211 = 1221203319263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221203321341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610601660655 + 610601660656.
It is an arithmetic number, because the mean of its divisors is an integer number (610601660656).
Almost surely, 21221203321311 is an apocalyptic number.
1221203321311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221203321311 is an equidigital number, since it uses as much as digits as its factorization.
1221203321311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1221203321311 its reverse (1131233021221), we get a palindrome (2352436342532).
The spelling of 1221203321311 in words is "one trillion, two hundred twenty-one billion, two hundred three million, three hundred twenty-one thousand, three hundred eleven".
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