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12212100122021 is a prime number
BaseRepresentation
bin1011000110110101100111…
…1000111100010110100101
31121020110120020212200020022
42301231121320330112211
53100040340112401041
641550054503444525
72400203140214132
oct261553170742645
947213506780208
1012212100122021
113989139171848
121452953756745
136a779982a777
143030d6b01589
151629e87e124b
hexb1b59e3c5a5

12212100122021 has 2 divisors, whose sum is σ = 12212100122022. Its totient is φ = 12212100122020.

The previous prime is 12212100122009. The next prime is 12212100122039. The reversal of 12212100122021 is 12022100121221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10768990444996 + 1443109677025 = 3281614^2 + 1201295^2 .

It is an emirp because it is prime and its reverse (12022100121221) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12212100122021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12212100122821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106050061010 + 6106050061011.

It is an arithmetic number, because the mean of its divisors is an integer number (6106050061011).

Almost surely, 212212100122021 is an apocalyptic number.

It is an amenable number.

12212100122021 is a deficient number, since it is larger than the sum of its proper divisors (1).

12212100122021 is an equidigital number, since it uses as much as digits as its factorization.

12212100122021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 12212100122021 its reverse (12022100121221), we get a palindrome (24234200243242).

The spelling of 12212100122021 in words is "twelve trillion, two hundred twelve billion, one hundred million, one hundred twenty-two thousand, twenty-one".