1221250433 has 8 divisors (see below), whose sum is σ = 1340008488. Its totient is φ = 1106037504.

The previous prime is 1221250427. The next prime is 1221250483. The reversal of 1221250433 is 3340521221.

It can be written as a sum of positive squares in 4 ways, for example, as 33965584 + 1187284849 = 5828^2 + 34457^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1221250433 - 2⁴ = 1221250417 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1221250399 and 1221250408.

It is not an unprimeable number, because it can be changed into a prime (1221250483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 885560 + ... + 886937.

It is an arithmetic number, because the mean of its divisors is an integer number (167501061).

Almost surely, 2^1221250433 is an apocalyptic number.

1221250433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1221250433 is a deficient number, since it is larger than the sum of its proper divisors (118758055).

1221250433 is a wasteful number, since it uses less digits than its factorization.

1221250433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1772563.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 1221250433 is about 34946.3937052166. The cubic root of 1221250433 is about 1068.8946669278.

Adding to 1221250433 its reverse (3340521221), we get a palindrome (4561771654).

The spelling of 1221250433 in words is "one billion, two hundred twenty-one million, two hundred fifty thousand, four hundred thirty-three".