Base | Representation |
---|---|
bin | 1011000110111000111110… |
… | …1101111101000101011110 |
3 | 1121020112220012012100120001 |
4 | 2301232033231331011132 |
5 | 3100044212310223402 |
6 | 41550324244044514 |
7 | 2400234414306661 |
oct | 261561755750536 |
9 | 47215805170501 |
10 | 12213003211102 |
11 | 3989561a13a61 |
12 | 1452b6609373a |
13 | 6a78b19661c5 |
14 | 303180a236d8 |
15 | 162a4cc2d187 |
hex | b1b8fb7d15e |
12213003211102 has 4 divisors (see below), whose sum is σ = 18319504816656. Its totient is φ = 6106501605550.
The previous prime is 12213003211063. The next prime is 12213003211147. The reversal of 12213003211102 is 20111230031221.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 12213003211102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3053250802774 + ... + 3053250802777.
It is an arithmetic number, because the mean of its divisors is an integer number (4579876204164).
Almost surely, 212213003211102 is an apocalyptic number.
12213003211102 is a deficient number, since it is larger than the sum of its proper divisors (6106501605554).
12213003211102 is an equidigital number, since it uses as much as digits as its factorization.
12213003211102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6106501605553.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12213003211102 its reverse (20111230031221), we get a palindrome (32324233242323).
The spelling of 12213003211102 in words is "twelve trillion, two hundred thirteen billion, three million, two hundred eleven thousand, one hundred two".
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