Base | Representation |
---|---|
bin | 1011000110111000111110… |
… | …1101111101000110001011 |
3 | 1121020112220012012100121201 |
4 | 2301232033231331012023 |
5 | 3100044212310224042 |
6 | 41550324244045031 |
7 | 2400234414310054 |
oct | 261561755750613 |
9 | 47215805170551 |
10 | 12213003211147 |
11 | 3989561a13aa2 |
12 | 1452b66093777 |
13 | 6a78b196622b |
14 | 303180a2372b |
15 | 162a4cc2d1b7 |
hex | b1b8fb7d18b |
12213003211147 has 2 divisors, whose sum is σ = 12213003211148. Its totient is φ = 12213003211146.
The previous prime is 12213003211063. The next prime is 12213003211169. The reversal of 12213003211147 is 74111230031221.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12213003211147 - 239 = 11663247397259 is a prime.
It is not a weakly prime, because it can be changed into another prime (12213003211187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106501605573 + 6106501605574.
It is an arithmetic number, because the mean of its divisors is an integer number (6106501605574).
Almost surely, 212213003211147 is an apocalyptic number.
12213003211147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213003211147 is an equidigital number, since it uses as much as digits as its factorization.
12213003211147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 12213003211147 its reverse (74111230031221), we get a palindrome (86324233242368).
The spelling of 12213003211147 in words is "twelve trillion, two hundred thirteen billion, three million, two hundred eleven thousand, one hundred forty-seven".
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