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12213003211147 is a prime number
BaseRepresentation
bin1011000110111000111110…
…1101111101000110001011
31121020112220012012100121201
42301232033231331012023
53100044212310224042
641550324244045031
72400234414310054
oct261561755750613
947215805170551
1012213003211147
113989561a13aa2
121452b66093777
136a78b196622b
14303180a2372b
15162a4cc2d1b7
hexb1b8fb7d18b

12213003211147 has 2 divisors, whose sum is σ = 12213003211148. Its totient is φ = 12213003211146.

The previous prime is 12213003211063. The next prime is 12213003211169. The reversal of 12213003211147 is 74111230031221.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12213003211147 - 239 = 11663247397259 is a prime.

It is not a weakly prime, because it can be changed into another prime (12213003211187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106501605573 + 6106501605574.

It is an arithmetic number, because the mean of its divisors is an integer number (6106501605574).

Almost surely, 212213003211147 is an apocalyptic number.

12213003211147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12213003211147 is an equidigital number, since it uses as much as digits as its factorization.

12213003211147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 12213003211147 its reverse (74111230031221), we get a palindrome (86324233242368).

The spelling of 12213003211147 in words is "twelve trillion, two hundred thirteen billion, three million, two hundred eleven thousand, one hundred forty-seven".